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Strong contrasts -- green gas and red smoke A remarkable compound (or mix of compounds) is prepared in this experiment. At high dilution, the vapor of this compound has a distinct green color, which shifts towards yellow on stronger heating. When the compound is poured at in cold air, then it immediately turns into a red/orange smoke.
When it condenses on a glass wall, then it forms a dark brown solid or a red/brown liquid. The precise nature of this compound is not entirely clear to me.
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Procedure for performing the experiment
On strong heating, a beautiful green/yellow gas is formed, which has a fairly intense color. The following picture shows this gas:
A video is available in which the formation of the green gas is shown, and it also shows the formation of the red/brown smoke, which settles on the glass a red liquid or a very dark brown solid: formation of green vapor (download size just over 7 MByte).
When the heating becomes somewhat stronger, then the color of the vapor shifts towards yellow again and the color becomes more intense. All of this is shown in a second video, which has a download size of almost 8 MByte. A more detailed picture of the red liquid, sticking to the glass and some of the collected liquid at the bottom is shown below. The picture also shows that the test tube is filled with a red smoke. This is not a red gas/vapor, but it really is a red smoke.
When the test tube is shaken, then all smoke quickly is absorbed by the water and all dark solid material, sticking to the glass, also quickly is absorbed and a turbid yellow/green liquid remains.
The liquid has a clear green hue and this can only be due to the presence of some blue vanadyl ion (which contains vanadium in the +4 oxidation state). The mix of yellow/brown vanadium pentoxide and some blue vanadyl gives the yellow/green color. The turbidity is due to the low solubility of the vanadium pentoxide.
Discussion of results What happens in this experiment cannot easily be explained from basic knowledge of certain compounds. Literature describes the following compounds of vanadium:
The observations in this experiment do not really match any of these compounds. The dark brown solid, which settles at the glass does not match the descriptions. The red liquid, formed in the second step of the experiment could be VCl4, but this does not match with its behavior on addition of water. VCl4 gives bright blue solutions, when water is added, and such behavior could not be reproduced.
Most likely, initially the following reaction occurs: V2O5 + 3PCl5 → 2VOCl3 + 3POCl3 From this reaction, other compounds are formed. If only VOCl3 and POCl3 were formed, then the liquid would become pale yellow and no dark brown solid and/or liquid would be formed. The dark brown solid also is a mystery compound. It cannot be VCl4, because that has a melting point of –28 °C. Could this be a mixed phosphorus/vanadium compound? The green vapor/gas could be VOCl3, but this is not really sure. Literature indeed mentions a green/yellow color for the vapor of VOCl3, but nothing is said about the intensity of the color and the effect of shifting towards yellow, when the concentration of the gas becomes higher and/or when the temperature becomes higher. The red/orange smoke almost certainly is V2O5 or some hydrated form of this. It is well-known that highly condensed species of general formula (V2O5∙xH2O)n can have deep red colors. This V2O5 is formed by hydrolysis in (humid) air: 2VOCl3 + (3+x)H2O → V2O5∙xH2O + 6HCl
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