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Formation of a remarkable
volatile molybdenum compound Molybdenum and its common compounds
all are non-volatile solids. This metal is used in
specialty metallurgical applications, and its compounds
are used in ceramics, as lubricant, and in the
laboratory. In this experiment, a volatile molybdenum
compound is made, which easily can be obtained in the
gaseous state and which can be refluxed in a test tube.
This experiment is quite spectacular, but it must be
carried out carefully.
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Production of molybdenum
pentachloride When the above instructions
are followed, then after a few seconds a sudden reaction
sets in, in which a lot of brown vapor is produced,
which quickly condenses to a very dark brown liquid,
which runs along the glass. When the test tube is
gently heated from below, then the brown liquid can be
kept refluxing in the test tube. The liquid, however,
slowly decomposes to a black solid, especially at the
spot, where the test tube is heated. This solid forms an
immobile crust on the glass, which is not volatile. Formation of the brown vapor
and the refluxing along the glass is shown in this video.
This video
shows how the volatile compound dissolves in the acid. Discussion of results The reactions, shown in this
experiment, are quite uncommon. Only few chemists know
this kind of chemistry of the element molybdenum.
3
PCl5 + MoO3 →
3 POCl3 +
MoCl6 The compound MoCl6 is not
stable, not even at room temperature, and certainly not
at the elevated temperatures of the heated test tube.
The compound MoCl6
quickly decomposes by splitting off a chlorine atom: 2 MoCl6 → 2 MoCl5 + Cl2 The compound MoCl5 is a
volatile compound, which easily forms dark red/brown
vapors and a very dark brown liquid. The solid is black.
In the solid state it exists as its dimer Mo2Cl10,
which has two bridging chlorine atoms between the two
molybdenum atoms. In the gas phase, it exists as
monomer. On stronger heating, the pentachloride
loses an additional chlorine atom, giving molybdenum(IV)
chloride. This in turn easily loses another chlorine
atom, giving molybdenum(III) chloride. Molybdenum(IV)
chloride is a black compound, which slowly dissolves in
water, giving black molybdenum(IV) oxo-compounds and
hydrogen chloride. Molybdenum(III) chloride is a very
dark red compound, insoluble in water.
![]() MoCl5 + H2O → MoOCl3 + 2 HCl In highly concentrated hydrochloric acid it forms a complex MoOCl3 · 2 HCl. Probably, in strongly acidic aqueous solution it exists as MoOCl52–. This complex has a bright green color. On dilution, there is further hydrolysis, which results in formation of a brown compound. The composition of that brown compound is not known to me, the author of this webpage. It most likely will have more oxygen atoms attached to the molybdenum atom and more chloride will have hydrolysed to HCl.
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