Description of experiment
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Needed compounds:
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hydrochloric acid : HCl
cupric chloride dihydrate : CuCl2 . 2H2O
cesium chloride : CsCl
Class:
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elem=Cl,Cu,Cs
coordination
Summary:
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Cesium forms a solid red/brown chloro complex of copper(II). This complex is
very remarkable, due to its rust-like color, which is very uncommon for
copper(II) salts.
Description:
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Dissolve some cesium chloride in a small amount of water. Assure that the
concentration is really high, so use a small amount of water.
In a separate test tube, dissolve some cupric chloride in concentrated
hydrochloric acid (the more concentrated, the better, preferrably 37% HCl by
weight). Also make the solution concentrated. The resulting solution is dark
olive green.
Add the two liquids to each other: The liquid becomes turbid and a very fine
precipitate is formed. This precipitate has a red/brown color where the
particles are somewhat larger, it is rust-like where the particles are small.
Put the slurry with the precipitate on a glass-fritte filter and soak the
liquid away: A rust-brown like paste remains.
Put some of the paste in water: It quickly dissolves, giving a green solution,
at higher dilution it gives a light blue solution.