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Description of experiment
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experiment.
Needed compounds: ----------------- sulphuric acid : H2SO4 sodium nitrite : NaNO2 sodium sulfide : Na2S . 3H2O
Class: ------ elem=N,S redox
Summary: -------- When sodium sulfide and sodium nitrite are mixed as solids, or when mixed in aqueous solution, no reaction occurs. Sulfide ion and nitrite ion can coexist in solution. When a very small amount of acid is added, a bright yellow/ochre solid compound is formed, which slowly turns lighter. When more acid is added, then the solid becomes almost white.
The very light yellow, almost white compound most likely is very finely divided elemental sulphur. The much brighter yellow/ochre definitely is not sulphur, its color is too strong and also differs quite a lot from the kind of yellow of sulphur.
Description: ------------ Take a tiny amount of solid sodium sulfide and add some solid sodium nitrite, assuring that the nitrite is in large excess: When the two solids are mixed, nothing happens.
Add some water: Both solids dissolve and the solution becomes colorless. Nothing special seems to happen. It seems that nitrite and sulfide ion can coexist in non-acidic solution.
Add a single drop of dilute sulphuric acid: The liquid at once becomes turbid. The precipitate has a bright yellow/ochre color, which differs a lot from the color of elemental sulphur, which is lighter yellow and also is purely yellow with no brown/orange hue. On shaking, the color becomes somewhat lighter, more like the well-known light yellow color of very finely divided sulphur.
Add more acid: Bubbles of gas are formed and the air above the liquid becomes light brown. The gas is nitrogen monoxide, the decomposition product of nitrite when it is strongly acidified. The very finely divided light yellow solid clumps together and the liquid becomes almost white and somewhat larger yellow particles float around in the liquid. These larger particles now most likely are sulphur. They have the same color as elemental sulphur (flowers of sulphur.
Remark: --------- The final reaction is that sulfide is oxidized to free sulphur by the nitrous acid formed on acidification of the sulfide/nitrite solution, but the nature of the intermediate bright yellow/ochre compound is unclear.
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