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Description of experiment
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experiment.
Needed compounds: ----------------- potassium iodide : KI sodium thiosulfate : Na2S2O3 . 5H2O nitric acid : HNO3 bismuth : Bi
Class: ------ elem=S,I,Bi coordination
Summary: -------- Bismuth forms a yellow complex with thiosulfate. In the presence of thiosulfate, it still forms a deep orange complex with iodide, just as without thiosulfate.
Description: ------------ Prepare a solution of bismuth nitrate by dissolving some bismuth metal in nitric acid. This takes quite some time. Initially the reaction is vigorous with evolution of a lot of brown NO2, but lateron the reaction is slow. Dilute the solution with water, such that the solution remains clear.
Dissolve quite some sodium thiosulfate in water and then add the clear and fairly acidic solution of bismuth nitrate: A light yellow precipitate is formed at once. It very much looks like sulphur, same type of yellow, same brightness. Above the yellow precipitate there still is colorless solution of sodium thiosulfate. The sodium thiosulfate was present in large excess amount.
Shake the liquid with the yellow precipitate: The precipitate dissolves again and the liquid becomes clear and bright yellow. There also is a faint smell of SO2, probably due to decomposition of thiosulfate.
Add some solid potassium iodide to the liquid: Around the crystals, the liquid becomes bright orange, when all iodide is dissolved, the liquid becomes bright yellow, even brighter than before. Still, the liquid is clear. This reaction is quite much like the reaction of excess iodide with bismuth, without thiosulfate being present.
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