|
Description of experiment
Below follows a plain text transcript of the selected
experiment.
Needed compounds: ----------------- hydroxyl amine sulfate : (NH3OH)2 SO4 sodium hydroxide : NaOH sodium sulfite : Na2SO3 sulphuric acid : H2SO4 vanadium pentoxide : V2O5
Class: ------ elem=V,N redox
Summary: -------- The result of this experiment is remarkable. Hydroxyl amine, being a strong reductor, appears to oxidize vanadium (IV) to vanadium (V) in alkaline environments. Or is there another compound, which strongly resembles the well-known yellow colour of vanadium (V) in acidic environments and the (almost) colourless appearance of vanadium (V) in alkaline environments?
Description: ------------ Add some sulphuric acid to a mixture of vanadium pentoxide and excess sodium sulfite and boil gently: All vanadium pentoxide is dissolved and a clear bright blue liquid is formed. Boiling is continued, until no smell of SO2 can be observed anymore above the blue liquid.
Add an excess amount of a solution of NaOH, neutralizing all acid: The liquid turns brown and remains clear. It becomes fairly dark. This is the colour of vanadate (IV) in alkaline environments.
Add a large excess amount of solid hydroxyl amine sulphate and heat: The liquid becomes lighter and lighter, until it is almost colorless (very light yellow). There is a faint smell of ammonia (or is this the smell of free hydroxyl amine, liberated in the strongly alkaline environment?). During the reaction a lot of gas is evolved, however, when the hydroxyl amine sulfate was added to the cooled down brown liquid, this was not yet the case. Apparently the red/brown vanadium (IV) compound is oxidized to an almost colorless vanadium (V) compound.
Add an excess amount of sulphuric acid: The liquid becomes intense yellow, however, within a minute this colour shifts to green/blue and a little while later, the liquid is almost completely blue. Apparently the colorless alkaline vanadium (V) is transformed in yellow/ orange vanadium (V) in acidic environment, which is reduced by excess hydroxyl ammonium ions, remaining from the excess hydroxyl amine sulfate.
|