Description of experiment
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experiment.
Needed compounds: ----------------- EDTA tetra sodium : (NaOOC CH2)2 N CH2 CH2 N (CH2 COONa)2 ascorbic acid : C6H8O6 sulphuric acid : H2SO4 sodium hydroxide : NaOH vanadium pentoxide : V2O5
Class: ------ elem=V coordination redox
Summary: -------- Vanadium (IV) does not build complexes with EDTA in acidic environments.
Description: ------------ Dissolve some V2O5 in a solution of NaOH and add an excess amount of sulfuric acid: The liquid becomes yellow, formation of pervanadyl ([VO2]+).
Add an excess amount of ascorbic acid: The liquid immediately becomes blue (vanadyl, [VO]2+) and it remains clear. The reaction is fast and complete.
Add some EDTA Na4: The solid dissolves and the liquid remains blue. No intensification of the color can be observed, nor a shift of color. Apparently EDTA does not build a coordination complex with vanadyl (at least not in strongly acidic environments) or the complex has the same color as free aqueous vanadyl.
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