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Description of experiment
Below follows a plain text transcript of the selected
experiment.
Needed compounds: ----------------- sulphuric acid : H2SO4 acetone : CH3 CO CH3 cupric chloride dihydrate : CuCl2 . 2H2O
Class: ------ elem=Cu,Cl coordination
Summary: -------- Cupric chloride dihydrate dissolves in acetone. The solution becomes yellow at low concentrations, green/brown at higher concentrations. When sulphuric acid is added, then a precipitate of anhydrous cupric chloride is formed.
Description: ------------ Add some solid CuCl2.2H2O to some acetone: The solid partly dissolves. The liquid becomes yellow and when more of the solid dissolves, then the liquid becomes green/brown. Where the acetone evaporates, a brown solid remains. The glass becomes covered with some brown/yellow crust, when the acetone evaporates. The liquid itself remains clear all the time.
Add a few drops of concentrated H2SO4 (96%): A brown precipitate is formed. The temperature of the liquid raises (when acetone and H2SO4 combine, then a fairly large amount of heat is generated).
Add a lot of water and shake well: The liquid becomes clear and light blue. All remaining solid cupric chloride now dissolves.
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