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Description of experiment
Below follows a plain text transcript of the selected
experiment.
Needed compounds: ----------------- sulphuric acid : H2SO4 cupric chloride dihydrate : CuCl2 . 2H2O
Class: ------ elem=Cu coordination
Summary: -------- Cupric chloride dihydrate is dehydrated by concentrated sulphuric acid.
Description: ------------ Add a few drops of concentrated H2SO4 (96%) to blue/green cupric chloride dihydrate: As soon as the acid touches the cupric chloride, the compound turns brown (the color of anhydrous cupric chloride). No gas is evolved. The latter is a remarkable difference with e.g. NaCl, which produces HCl-gas, when treated with concentrated H2SO4.
Quickly add a large amount of water: The acid and the brown solid dissolve. Around the brown solid, the liquid becomes green, but when everything is dissolved, the liquid becomes light blue.
BEWARE: Only use a very small amount of H2SO4, relative to the amount of water and add the water to the acid at once!
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