Description of experiment
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experiment.
Needed compounds: ----------------- potassium iodide : KI lead acetate : Pb(CH3COO)2 . 3H2O
Class: ------ precipitate
Summary: -------- Lead (II) forms a brightly colored precipitate with iodide ions. This precipitate is soluble in water fairly well, when hot.
Description: ------------ Prepare a solution of lead acetate and add one drop of dilute acetic acid (appr. 5% Ch3COOH) to this solution in order to make it clear. It is really important to use distilled water for this solution.
To the solution of lead acetate add a solution of potassium iodide: A bright yellow precipitate is formed immediately.
Heat the liquid until it is close to boiling: An appreciable amount of the precipitate dissolves. The liquid becomes colorless. The yellow precipitate dissolves as colorless compound in water.
Let liquid cool down slowly: Many small glittering crystals of lead iodide are formed. These slowly settle at the bottom of the test tube.
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